The sum of two numbers is -62. Twice the first minus the second is 41. Find the numbers.
X+y= -62
2x+y = 41
------------------
2x+2y= -124
2x+y= 41
- - -
---------------------
Y= 175
Whats answer
To solve this problem, let's assign variables to the unknown numbers. Let's say the first number is "x" and the second number is "y".
According to the problem, the sum of two numbers is -62, so we can set up the equation:
x + y = -62 ---(Equation 1)
It is also given that twice the first number minus the second number is 41, so we can set up another equation:
2x - y = 41 ---(Equation 2)
Now we have a system of equations with two variables (x and y).
To solve this system, we can use the method of substitution or elimination. Let's use the substitution method in this case.
From Equation 1, we can express y in terms of x by subtracting x from both sides:
y = -62 - x
Now we substitute this expression for y in Equation 2:
2x - (-62 - x) = 41
2x + 62 + x = 41
3x + 62 = 41
3x = 41 - 62
3x = -21
x = -21 / 3
x = -7
Now that we have the value of x, we can substitute it back into Equation 1 to find the value of y:
-7 + y = -62
y = -62 + 7
y = -55
Therefore, the two numbers are -7 and -55.