Question

Did I solve this problem correctly?

(b-8)^2
(b)^2= b^2
(-8)^2= 64
b^2 + 64
If not how do I fix it?

Answer 1

( x - y ) ^ 2 = x ^ 2 - 2 x y + y ^ 2

( b - 8 ) ^ 2 = b ^ 2 - 2 b * 8 + 8 ^ 2 = b ^ 2 - 16 b + 64