How would you prepare 100 ml of the following aqueous solution: 25 mM

TrisCl, 50 mM EDTA, 2% (w/v) NaCl, 5 X M9? You have been provided with stock
solutions of 1 M TrisCl, 0.5 M EDTA, 25 X M9 and crystals of NaCl.

To prepare a 100 ml aqueous solution with the given concentrations of TrisCl, EDTA, NaCl, and M9, you will need to calculate the amounts of each component from their respective stock solutions and crystals.

Let's start with TrisCl:

1. Calculate the volume of the 1 M TrisCl stock solution needed to make a 25 mM solution.

Volume of 1 M TrisCl stock solution = (Desired final concentration / Stock concentration) * Volume of final solution
= (25 mM / 1000 mM) * 100 ml
= 2.5 ml of 1 M TrisCl stock solution

Next, let's calculate the amount of EDTA:

2. Calculate the volume of the 0.5 M EDTA stock solution needed to make a 50 mM solution.

Volume of 0.5 M EDTA stock solution = (Desired final concentration / Stock concentration) * Volume of final solution
= (50 mM / 500 mM) * 100 ml
= 10 ml of 0.5 M EDTA stock solution

Now, let's determine the amount of NaCl:

3. Calculate the mass of the NaCl crystals needed to prepare a 2% (w/v) solution.

Mass of NaCl crystals = (Desired mass / Concentration) * Volume of final solution
= (2 g / 100 ml) * 100 ml
= 2 g of NaCl crystals

Finally, let's calculate the volume of the M9 stock solution:

4. Calculate the volume of the 25X M9 stock solution needed to make a 5X M9 solution.

Volume of 25X M9 stock solution = (Desired final concentration / Stock concentration) * Volume of final solution
= (5X M9 / 25X M9) * 100 ml
= 20 ml of 25X M9 stock solution

Therefore, to prepare 100 ml of the given aqueous solution, you will need:
- 2.5 ml of 1 M TrisCl stock solution
- 10 ml of 0.5 M EDTA stock solution
- 2 g of NaCl crystals
- 20 ml of 25X M9 stock solution

You can combine these components in a suitable container, adding them one by one and making sure they dissolve completely to obtain the desired solution.