How many moles of chloride ions are in 0.2580 g of aluminum chloride?
how many moles of AlCl3 is .2580g?
Look at the formula for the compound. You will have 3 times that many moles of Cl ions.
To find the number of moles of chloride ions in aluminum chloride, we need to use its molar mass and the given mass of the compound.
The molar mass of aluminum chloride (AlCl₃) can be calculated by adding the atomic masses of its constituent elements, aluminum (Al) and chlorine (Cl):
Molar mass (Al) = 26.98 g/mol
Molar mass (Cl) = 35.45 g/mol
Since there are three chlorine atoms in one molecule of aluminum chloride, we multiply the molar mass of chlorine by 3:
Molar mass (AlCl₃) = (26.98 g/mol) + (3 × 35.45 g/mol) = 133.34 g/mol
Now we can use the molar mass to convert the given mass of aluminum chloride (0.2580 g) into moles. We divide the mass by the molar mass:
Number of moles = Mass / Molar mass
Number of moles = 0.2580 g / 133.34 g/mol
Calculating this gives us:
Number of moles = 0.0019 mol
Therefore, there are 0.0019 moles of chloride ions in 0.2580 g of aluminum chloride.