1.)what is the magnitude of the force experienced by a proton moving at 3 km/s inside magnetic field of strength 0.05T

2.)an electron is moving at 2x10^5 m/s through a uniform magnetic field of 1.4x10^-3 T.what is the magnitude of magnetic force if the velocity of the electron and the field make an angle of 45 degree.

Hey, I answered this hours ago:

http://www.jiskha.com/display.cgi?id=1442934045

Please Complete Solution please i don't understand.

To calculate the magnitude of the force experienced by a charged particle moving in a magnetic field, you can use the formula:

F = q * v * B * sin(θ)

Where:
F is the magnitude of the force
q is the charge of the particle (in this case, either the charge of a proton or the charge of an electron)
v is the velocity of the particle
B is the magnetic field strength
θ is the angle between the velocity vector and the magnetic field vector

1.) For the first question, a proton is moving at 3 km/s inside a magnetic field of strength 0.05 T. The charge of a proton is +1.6 x 10^-19 C. Therefore, plugging the values into the formula:

F = (1.6 x 10^-19 C) * (3 x 10^3 m/s) * (0.05 T) * sin(θ)

Since the question does not provide the angle between the velocity and the magnetic field, we assume they are perpendicular (θ = 90 degrees), which means sin(θ) = 1. Substituting the values:

F = (1.6 x 10^-19 C) * (3 x 10^3 m/s) * (0.05 T) * 1

F = 2.4 x 10^-14 N

Therefore, the magnitude of the force experienced by the proton is 2.4 x 10^-14 N.

2.) For the second question, an electron is moving at 2 x 10^5 m/s through a magnetic field of strength 1.4 x 10^-3 T. The charge of an electron is -1.6 x 10^-19 C. The angle between the velocity and the magnetic field is given as 45 degrees. Plugging the values into the formula:

F = (-1.6 x 10^-19 C) * (2 x 10^5 m/s) * (1.4 x 10^-3 T) * sin(45 degrees)

Since sin(45 degrees) = sqrt(2)/2 ≈ 0.7071, we substitute the value into the formula:

F = (-1.6 x 10^-19 C) * (2 x 10^5 m/s) * (1.4 x 10^-3 T) * 0.7071

F ≈ -3.519 x 10^-14 N

Since the magnitude of a force is always positive, the magnitude of the magnetic force experienced by the electron in this case is approximately 3.519 x 10^-14 N.