1.)what is the magnitude of the force experienced by a proton moving at 3 km/s inside magnetic field of strength 0.05T
2.)an electron is moving at 2x10^5 m/s through a uniform magnetic field of 1.4x10^-3 T.what is the magnitude of magnetic force if the velocity of the electron and the field make an angle of 45 degree.
my physics skills are rusty
F = q (V x B)
we need to know the angle between V and B.
I suspect it is 90 degrees
q = 1.6 * 10^-19
V = 3,000
B = .05
then F = 1.6*10^-19 * 3 * 10^3 * 5 * 10^-2 N
second one the same way but use
V x B = |V| |B| sin theta
To calculate the magnitude of the force experienced by a charge moving in a magnetic field, you can use the formula:
F = q * v * B * sin(θ),
where:
- F is the magnitude of the force,
- q is the charge of the particle (proton or electron),
- v is the velocity of the particle,
- B is the strength of the magnetic field, and
- θ is the angle between the velocity vector and the magnetic field vector.
1.) For the first question, a proton is moving at 3 km/s inside a magnetic field of strength 0.05 T. Since we are dealing with a proton, we know that the charge of a proton is 1.6 × 10^(-19) C. Therefore, we can substitute these values into the formula:
F = (1.6 × 10^(-19) C) * (3 km/s) * (0.05 T) * sin(θ),
Here, we are not given the angle θ, so we can assume it to be 0 degrees, which means the velocity and magnetic field are parallel. With this assumption, sin(0) equals 0, so the magnetic force on the proton will be 0.
Therefore, the magnitude of the force experienced by the proton is 0 N.
2.) For the second question, an electron is moving at 2 × 10^5 m/s through a uniform magnetic field of 1.4 × 10^(-3) T, and the velocity of the electron and the field make an angle of 45 degrees. By substituting the given values into the formula:
F = (1.6 × 10^(-19) C) * (2 × 10^5 m/s) * (1.4 × 10^(-3) T) * sin(45°),
Since the sine of 45 degrees is 1/√2 or approximately 0.707, we can simplify the calculation as:
F ≈ (1.6 × 10^(-19) C) * (2 × 10^5 m/s) * (1.4 × 10^(-3) T) * 0.707,
Now, we can multiply these values to get the magnitude of the force.
F ≈ 2.24 × 10^(-17) N.
Therefore, the magnitude of the magnetic force experienced by the electron is approximately 2.24 × 10^(-17) N.