I cannot figure out this question, and it would be greatly appreciated if someone could help me out! :)
It has been claimed that an insect is the best jumper in the animal kingdom. This insect can accelerate at 3950 m/s2 over a distance of 2.3 mm as it straightens its legs.
(a) Assuming a uniform acceleration, what is the velocity of the insect after it has accelerated through this short distance, and how long did it take to reach that velocity?
(b) How high would the insect jump if air resistance could be ignored? Note that the actual height obtained is about 0.7 m, so air resistance is important here.
Thank you!
(a) Velocity(v)=(2 X 3950 X 0.0023 )^1/2
Time(t)=?
s=1/2 X a X t^2
or,t=((2 X s)/a)^1/2
Here, a=3950 m/s2
s=2.3 mm=0.0023 m
(b) I Think , For Verical Motion Initial Velocity Needs To Be Mentioned.