Imagine that you have a stock solution with a concentration of 4.6 M glucose (C1).

You want to use the stock solution to prepare a diluted solution of 0.22M glucose (C2).
You need a total volume of 10mL of 0.22M glucose (V2).
What volume of water you need to use for making 0.22M glucose? Express your answer in mL

I got 478.26

The other I couldn't figure out... I'm not sure how to distinguish between the two.

Imagine that you have a stock solution with a concentration of 4.6 M glucose (C1).
You want to use the stock solution to prepare a diluted solution of 0.22M glucose (C2).
You need a total volume of 10mL of 0.22M glucose (V2).
What volume of the stock solution would you need to use for making 0.22M glucose? Express your answer in mL.

To find the volume of water needed to make a 0.22M glucose solution with a total volume of 10mL, we can use the formula for dilution:

C1V1 = C2V2

where C1 is the initial concentration (4.6 M), V1 is the initial volume (unknown in this case), C2 is the final concentration (0.22 M), and V2 is the final volume (10 mL).

We can rearrange the formula to solve for V1:

V1 = (C2V2) / C1

Plugging in the given values, we have:

V1 = (0.22 M x 10 mL) / 4.6 M
V1 = 0.478 mL

Therefore, you would need to add 0.478 mL of water to the stock solution to make a 0.22M glucose solution with a total volume of 10mL.

Now, let's move on to the second question.

To find the volume of the stock solution needed to make a 0.22M glucose solution with a total volume of 10mL, we can again use the formula for dilution:

C1V1 = C2V2

where C1 is the initial concentration (4.6 M), V1 is the initial volume (unknown in this case), C2 is the final concentration (0.22 M), and V2 is the final volume (10 mL).

We can rearrange the formula to solve for V1:

V1 = (C2V2) / C1

Plugging in the given values, we have:

V1 = (0.22 M x 10 mL) / 4.6 M
V1 = 0.478 mL

So, you would need to use 0.478 mL of the stock solution to make a 0.22M glucose solution with a total volume of 10mL.