f 5 times the first number plus 3 times the second number equals 47, and 10 times the first number minus 4 times the second number equals 54, what are the numbers?
1st number = X.
2nd number = Y.
Eq1: 5x + 3y = 47.
Eq2: 10x - 4y = 54.
Solve the Eqs using the Elimination Method: Multiply Eq1 by -2 and add the
Eqs.