Fifty four decreased by three times a number is equal to the number increased by 10
54 - 3x = x+10
etc
if 9 is sabtracted from twice a number and rasult is 11 find the number
To solve this problem, we first need to translate the given statement into an equation.
Let's denote the unknown number as "x."
"Fifty-four decreased by three times a number" can be written as "54 - 3x."
"The number increased by 10" can be written as "x + 10."
According to the problem, these two expressions are equal, so we can set up the equation:
54 - 3x = x + 10
To solve for x, we need to isolate it on one side of the equation. We can do this by performing algebraic operations to both sides:
54 - 3x + 3x = x + 10 + 3x
54 = 4x + 10
Next, we want to isolate x, so we subtract 10 from both sides:
54 - 10 = 4x + 10 - 10
44 = 4x
Finally, we solve for x by dividing both sides by 4:
44/4 = 4x/4
11 = x
Therefore, the value of x is 11.