How many atoms of mercury are present in

3.2 cubic centimeters of liquid mercury?
The density of mercury is 13.55 g/cc.
Answer in units of atoms.

density=mass/volume

13.55*3.2=43.36g

1 mole of Hg=200.59

0.2 mole=43.36g

mole=number of atom/avogadroes number

atom=0.2*6.02*10^23

atom=1.204*10^23

mass Hg = volume x density = ?

200.59 g Hg contains 6.02E23 atoms Hg. So ? g Hg will have ...... atoms Hg.

To calculate the number of atoms of mercury in a given volume, we need to convert the volume to mass and then use the molar mass of mercury to find the number of atoms.

Step 1: Convert the volume to mass.
Given volume of liquid mercury = 3.2 cubic centimeters
Density of mercury = 13.55 g/cc

Mass = Volume x Density
Mass = 3.2 cc x 13.55 g/cc

Step 2: Calculate the number of moles of mercury.
Molar mass of mercury (Hg) = 200.59 g/mol (rounded)

Number of moles = Mass / Molar mass
Number of moles = (3.2 cc x 13.55 g/cc) / 200.59 g/mol

Step 3: Calculate the number of atoms of mercury.
Avogadro's number = 6.022 x 10^23 atoms/mol

Number of atoms = Number of moles x Avogadro's number
Number of atoms = [(3.2 cc x 13.55 g/cc) / 200.59 g/mol] x (6.022 x 10^23 atoms/mol)

Calculating this expression will give you the number of atoms of mercury in 3.2 cubic centimeters of liquid mercury.

To determine the number of mercury atoms in 3.2 cubic centimeters of liquid mercury, you'll need to follow these steps:

1. Calculate the mass of the mercury using the density: density = mass/volume.
- Given density: 13.55 g/cc
- Given volume: 3.2 cc
- Rearranging the formula: mass = density × volume

Plugging in the values: mass = 13.55 g/cc × 3.2 cc = 43.36 g

2. Calculate the number of moles of mercury using its molar mass. The molar mass of mercury (Hg) is 200.59 g/mol.

Number of moles = mass / molar mass
Plugging in the values: number of moles = 43.36 g / 200.59 g/mol ≈ 0.216 mol

3. Finally, determine the number of atoms using Avogadro's number. Avogadro's number is 6.0221 x 10^23 atoms/mol.

Number of atoms = number of moles × Avogadro's number
Plugging in the values: number of atoms = 0.216 mol × 6.0221 x 10^23 atoms/mol ≈ 1.304 x 10^23 atoms

Therefore, there are approximately 1.304 x 10^23 atoms of mercury present in 3.2 cubic centimeters of liquid mercury.