Please I need help with this problem.
it took us 3 hour to drive to a concert.on his way home he increased his speed by 19 miles got home in 2 hours . what was the speed?
thank you
To solve this problem, we can use the formula:
Speed = Distance / Time.
Let's break down the information given in the problem:
1. The original trip to the concert took 3 hours.
2. On the way back, the speed was increased by 19 miles per hour.
3. The return trip took 2 hours.
Since the distance of the trip remains the same, we can use the formula to find the speed for each trip and compare them.
For the original trip:
Speed1 = Distance / Time1
For the return trip:
Speed2 = Distance / Time2
Since we know that the distance is the same for both trips, we can set up the following equation:
Distance / Time1 = Distance / Time2
Now, let's substitute the values we have:
Distance / 3 = Distance / 2
To solve for the distance, we can cross-multiply:
2 * Distance = 3 * Distance
Simplifying the equation, we get:
2 * Distance - 3 * Distance = 0
Simplifying further, we find that:
- Distance = 0
However, this implies that the distance is zero, which is not possible. Therefore, there seems to be an error in the problem statement. Please double-check the information given in the problem, and I'll be glad to assist you further.
Let x = speed
3x = 2(x+19)
Solve for x.