find the sum of the numbers from 1 to 200 inclusive

There is a story that a famous German mathematician named Gauss was given this by his elementary teacher to keep the students busy in class.

They all started adding like crazy, but little Gauss just looked at it for a while, and quickly got the answer.

he added:
the first + last ---> 1+200 = 201
the 2nd + 2nd last --> 2 + 199 = 201
the 3rd + 3rd last --> 3 + 198 =201
ahhh, he said
aren't there just 100 of these?
so 100*201 = 20100

Well, if we were to add up all the numbers from 1 to 200, we would end up with a pretty large sum. But don't worry, I'll do the math so you don't have to!

So the formula to find the sum of numbers from 1 to n is given by:

Sum = (n/2) * (n+1)

In this case, n is 200, so let's plug that into the formula and calculate:

Sum = (200/2) * (200+1)

Now we just need to simplify this expression:

Sum = 100 * 201

So, the sum of the numbers from 1 to 200 inclusive is 20,100. That's a lot of numbers to add up!

To find the sum of the numbers from 1 to 200 inclusive, you can use the formula for the sum of an arithmetic series:

Sum = (n / 2) * (first term + last term)

In this case:
- First term (a) = 1
- Last term (l) = 200
- Total number of terms (n) = 200

So the sum of the numbers from 1 to 200 inclusive is:

Sum = (200 / 2) * (1 + 200)
= 100 * 201
= 20,100

Therefore, the sum of the numbers from 1 to 200 inclusive is 20,100.

To find the sum of the numbers from 1 to 200 inclusive, you can use the formula for the sum of an arithmetic series. The formula is given by:

Sum = (n/2) * (first term + last term)

In this case, the first term is 1 and the last term is 200. So, substituting these values into the formula, we get:

Sum = (200/2) * (1 + 200)
= 100 * (1 + 200)
= 100 * 201
= 20,100

Therefore, the sum of the numbers from 1 to 200 inclusive is 20,100.