The specific heat of a certain type of cooking oil is 1.75 cal/(g·°C). How much heat energy is needed to raise the temperature of 2.83 kg of this oil from 23 °C to 191 °C?

q = mass oil x specific heat oil x (Tfinal- Tinitial)

The specific heat of a certain type of cooking oil is 1.75 cal/(g·°C). How much heat energy is needed to raise the temperature of 2.06 kg of this oil from 23 °C to 191 °C?

To calculate the heat energy needed to raise the temperature of a substance, we can use the formula:

Q = m × c × ΔT

Where:
Q = Heat energy (in calories)
m = Mass of the substance (in grams)
c = Specific heat capacity of the substance (in cal/(g·°C))
ΔT = Change in temperature (in °C)

Given:
m = 2.83 kg = 2830 g
c = 1.75 cal/(g·°C)
ΔT = (191 °C) - (23 °C) = 168 °C

Let's substitute the given values into the formula and calculate the heat energy:

Q = 2830 g × 1.75 cal/(g·°C) × 168 °C
Q = 832,260 cal

Therefore, the heat energy needed to raise the temperature of 2.83 kg of this cooking oil from 23 °C to 191 °C is 832,260 calories.

To calculate the heat energy needed to raise the temperature of a substance, you can use the formula:

Q = m * c * ΔT

where:
Q represents the heat energy,
m is the mass of the substance,
c is the specific heat capacity of the substance, and
ΔT is the change in temperature.

In this case, the mass of the cooking oil is 2.83 kg, the specific heat capacity is 1.75 cal/(g·°C), and the change in temperature is (191 °C - 23 °C) = 168 °C.

To use the formula, we need to convert the mass from kg to grams and the specific heat capacity from cal/(g·°C) to cal/(kg·°C).

To convert the mass:
2.83 kg * 1000 g/kg = 2830 g

To convert the specific heat capacity:
1.75 cal/(g·°C) * 1 kg/1000 g = 0.00175 cal/(g·°C)

Now we have all the values needed, so we can calculate the heat energy:

Q = 2830 g * 0.00175 cal/(g·°C) * 168 °C

Q ≈ 833.04 cal

Therefore, approximately 833.04 calories (cal) of heat energy are needed to raise the temperature of 2.83 kg of the cooking oil from 23 °C to 191 °C.