3 years ago, Vin’s age is 3 times the age of Paul. At the present, Vin’s age is twice the age of Paul. What would be their age 3 years from now if the sum of their present age is 18?

Josh is 49 inches tall. His father is 70 inches tall. What is the percent that is equal to the ratio of Josh's height to his father's?

v-3 = 3(p-3)

v = 2p
v+p=18

clearly Vin is 12 and Paul is 6

You can do that without the first condition at all.

Jill said eight times my age is three years ago equals 104 how old is Jill now

a man's age is 120% of what it was 8 years ago. what is his present age answer

To solve this problem, we can use algebraic equations. Let's assign variables to represent Vin's and Paul's present ages. Let's say Vin's present age is represented by "V" and Paul's present age is represented by "P". Based on the given information, we can create two equations:

1) Three years ago, Vin’s age was 3 times the age of Paul: V - 3 = 3(P - 3)
2) At the present, Vin’s age is twice the age of Paul: V = 2P

Now, we need to solve these equations simultaneously to find their present ages. Let's start with equation 2 and isolate V:

V = 2P

Next, substitute this value of V in equation 1:

2P - 3 = 3(P - 3)
2P - 3 = 3P - 9
2P - 3P = -9 + 3
-P = -6
P = 6

Now that we know Paul's present age is 6, we can substitute this value back into equation 2 to find Vin's age:

V = 2P
V = 2(6)
V = 12

So, Vin's present age is 12 and Paul's present age is 6.

Next, we need to find their ages three years from now. To do this, we'll add 3 to their present ages:

Vin's age three years from now: V + 3 = 12 + 3 = 15
Paul's age three years from now: P + 3 = 6 + 3 = 9

Therefore, Vin's age three years from now would be 15 and Paul's age three years from now would be 9.