lim
x-->-9 x^2+10x+9 / x-9
limit as x goes to what ?
To find the limit of a function, we can substitute the value that x approaches into the function and evaluate it. In this case, we want to find the limit as x approaches -9 of the function (x^2 + 10x + 9) / (x - 9).
Let's substitute -9 into the function and simplify:
(-9)^2 + 10(-9) + 9 / -9 - 9
81 - 90 + 9 / -18
0 / -18
0
Therefore, the limit as x approaches -9 of the given function is 0.