A speed skater moving across frictionless ice at 8.3 m/s hits a 5.6 m -wide patch of rough ice. She slows steadily, then continues on at 6.5 m/s

What is he acceleration on the rough ice?

V^2 = Vo^2 + 2a*d.

V = 6.5 m/s.
Vo = 8.3 m/s.
d = 5.6 m.
a = ?. It should be negative.

To find the acceleration on the rough ice, we can use the formula for acceleration:

acceleration = (final velocity - initial velocity) / time

In this case, the initial velocity (v₁) is 8.3 m/s, and the final velocity (v₂) is 6.5 m/s.

First, we need to find the time it takes for the skater to slow down from 8.3 m/s to 6.5 m/s. Since acceleration is defined as the rate of change of velocity, we can use the equation:

acceleration = (v₂ - v₁) / t

Rearranging the equation to solve for time:

t = (v₂ - v₁) / acceleration

Substituting the given values:

t = (6.5 m/s - 8.3 m/s) / acceleration

Now, we need to find the distance covered during this time. The distance (d) covered while decelerating can be calculated using the formula:

d = v₁ * t + 0.5 * acceleration * t²

Substituting the known values:

5.6 m = 8.3 m/s * t + 0.5 * acceleration * t²

Now we have two equations:

1) t = (6.5 m/s - 8.3 m/s) / acceleration
2) 5.6 m = 8.3 m/s * t + 0.5 * acceleration * t²

We can use these two equations to solve for the acceleration.

By substituting the value of t from equation 1 into equation 2, we can solve for acceleration. However, since this is a nonlinear equation, it might not have a straightforward analytical solution.

One approach to finding the solution is to use numerical methods such as the bisection method or Newton's method. These methods involve iteratively guessing and improving the value of the acceleration until we find a solution that satisfies the equation. However, this process is beyond the scope of this explanation.

Alternatively, if you have the value of time or acceleration, you can substitute it back into either equation to find the other unknown.

In this particular case, without additional information about time or the value of acceleration, it is not possible to determine the exact acceleration on the rough ice.