Eight years ago, Heather was twice as old as her brother David. Today, she is 12 years older than him. How

old is Heather now?

Let H be heather's age now. D is Davids age now.

H-8=2(D-8)
H=D+12

Does that help?

To find out Heather's current age, we need to solve the problem step by step.

Let's assume that Heather is currently x years old, and her brother David is currently y years old.

According to the problem, eight years ago, Heather was twice as old as David. So, we can write the equation:

x - 8 = 2(y - 8) -- equation 1

Now, the problem also states that today, Heather is 12 years older than David. We can write another equation using this information:

x = y + 12 -- equation 2

To find Heather's current age, we need to solve equations 1 and 2 simultaneously.

First, we can substitute the value of x from equation 2 into equation 1:

(y + 12) - 8 = 2(y - 8)
Simplifying this equation, we get:

y + 4 = 2y - 16

Rearranging the equation, we have:

2y - y = 4 + 16
y = 20

Substituting the value of y back into equation 2, we can find Heather's current age:

x = 20 + 12
x = 32

Therefore, Heather is currently 32 years old.