Please help or list steps of how to do it
There are 3 white marbles and 7 blue marbles in a bag. Jamie will randomly pick two marbles out of the bag without replacing the first marble chosen. What is the probability of Jamie picking two blue marbles?
A)
1/
15
B)
1/
7
C)
21/
50
D)
7/
15
You do not need to press "return" to put in the denominator in a fraction.
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
7/10 * (7-1)/(10-1) = ?
7/15
Thanks
To calculate the probability of Jamie picking two blue marbles, we need to determine the total number of possible outcomes and the favorable outcomes.
Step 1: Determine the total number of possible outcomes.
Since Jamie is picking two marbles without replacing the first marble chosen, there are a total of 10 marbles in the bag during the first pick and 9 marbles in the bag during the second pick. Therefore, the total number of possible outcomes is given by 10 multiplied by 9, which equals 90.
Step 2: Determine the number of favorable outcomes.
To have two blue marbles, Jamie needs to pick a blue marble on the first pick and another blue marble on the second pick. The probability of picking a blue marble on the first pick is 7/10 since there are 7 blue marbles out of a total of 10 marbles left in the bag. After picking a blue marble on the first pick, the probability of picking another blue marble on the second pick is 6/9 since there are now 6 blue marbles left out of a total of 9 marbles. Therefore, the number of favorable outcomes is given by (7/10) multiplied by (6/9), which simplifies to 42/90.
Step 3: Calculate the probability.
The probability is given by the number of favorable outcomes divided by the total number of possible outcomes. So, the probability of Jamie picking two blue marbles can be calculated as (42/90) divided by 1, which gives 42/90.
Simplifying the fraction, we find that 42/90 equals 7/15.
Therefore, the correct answer is D) 7/15.