Simply the equation:

2x^4y^0z^2/(yz^2)^-2 x 2zx^2y^-4

Can you help?
I got the denominator to be
y^-6 x 2z^5 x x^2

When I solved it, I got
x^2y^6/z^3

ok, first of all you can't "solve" this because you need an equation to solve. You don't have one

secondly, you are using x as a variable, but then seem to use x as a multiplication sign, very confusing.

thirdly, you lack of brackets make the question ambiguous.
I will assume you mean:
simplify the expression 2x^4y^0z^2/( (yz^2)^-2 x 2zx^2y^-4)
= 2x^4z^2/((y^-2 z^-4)(2z x^2 y^-4))
= 2x^4z^2/(2y^-6 x^2 z^-3)
= x^2 y^6 z^5

I didn't ask for the problem to be solved, just simplified.

I know I shouldn't have used an x for a multiplication sign, sorry. My bad.
Thank you. I found my error.

Sure! Let's break down the steps to simplify the given equation:

Step 1: Simplifying the numerator.
The numerator of the equation is 2x^4y^0z^2. Any number or variable with an exponent of 0 is equal to 1. So, y^0 can be replaced with 1, which leaves us with 2x^4z^2.

Step 2: Simplifying the denominator.
The denominator is (yz^2)^-2 x 2zx^2y^-4. According to the power of a power rule, when raising a power to another power, you multiply the exponents. So, we can rewrite yz^2 raised to the power of -2 as (y^-2)(z^2 x -2) = y^-2z^-4. The denominator then becomes y^-2z^-4 x 2zx^2y^-4.

Now, let's simplify the denominator further:
- y^-2z^-4 x 2zx^2y^-4 = (1/y^2)(1/z^4) x 2zx^2(1/y^4) = (2z/x^2y^2z^4)(1/y^4) = 2z/x^2y^6z^4.

Step 3: Simplifying the entire equation.
Now that we have simplified the numerator and denominator, let's divide the numerator by the denominator:
(2x^4z^2) / (2z/x^2y^6z^4) = 2x^4z^2 x x^2y^6z^4 / 2z
= 2x^6y^6z^6 / 2z
= x^6y^6z^6/z
= x^6y^6z^5.

So, the simplified form of the equation is x^6y^6z^5.

Remember to double-check your work to ensure accuracy!