if you add 15.ml of a 0.250M HCl solution to 50.0ml of a 0.125 MHCl solution what will be the molarity of the resulting solution
it would be
(.25*.015 + .125*.050)/(.015+.050) = 0.1538M
Thank you Steve our answers are corresponding 100%.
A) Calculate the hydrogen ions (H+) concentration in an aqueous solution with the pH of 12.00.
B) What is the hydroxide ion concentration (OH-) of the above solution?
C) What is its pOH?
D What is the pH of a 0.035M solution of acetic acid (CH3COOH), pKa=4.74.
E) A 1.15M aqeous solution of formic acid (HOOH) has a pH of 1.83. What is the Ka of formic acid?
To find the molarity of the resulting solution, you need to consider the total volume of the solution after mixing the two solutions together.
First, let's calculate the moles of HCl in each solution:
For the 15.0 ml of 0.250 M HCl solution:
Molarity (M) = moles (mol) / volume (L)
0.250 M = moles / 0.015 L
Rearranging the equation:
moles = Molarity * volume
moles = 0.250 mol/L * 0.015 L
moles = 0.00375 mol HCl
For the 50.0 ml of 0.125 M HCl solution:
Molarity (M) = moles (mol) / volume (L)
0.125 M = moles / 0.050 L
Rearranging the equation:
moles = Molarity * volume
moles = 0.125 mol/L * 0.050 L
moles = 0.00625 mol HCl
Now, let's add the moles of HCl from each solution together:
Total moles of HCl = moles from 15.0 ml solution + moles from 50.0 ml solution
Total moles of HCl = 0.00375 mol + 0.00625 mol
Total moles of HCl = 0.01 mol
Next, we need to find the total volume of the resulting solution:
Total volume = volume of 15.0 ml solution + volume of 50.0 ml solution
Total volume = 15.0 ml + 50.0 ml
Total volume = 65.0 ml
Finally, we can calculate the molarity of the resulting solution:
Molarity = moles / volume
Molarity = 0.01 mol / 0.065 L (Converting ml to L)
Molarity ≈ 0.154 M
Therefore, the molarity of the resulting solution is approximately 0.154 M.