What is the factor of safety for a steel hanger having an ultimate strength of 70,000 Newton per
cm2 and supporting a load of 89.6 kN.The hanger has a cross sectional area of 6.4 cm2.
To calculate the factor of safety for the steel hanger, we need to compare the applied load to the maximum load the hanger can support.
Step 1: Convert the applied load to Newton:
89.6 kN * 1000 N/kN = 89,600 N
Step 2: Calculate the maximum load the hanger can support:
Maximum load = Ultimate Strength * Cross-sectional Area
Maximum load = 70,000 N/cm^2 * 6.4 cm^2 = 448,000 N
Step 3: Calculate the factor of safety:
Factor of Safety = Maximum load / Applied load
Factor of Safety = 448,000 N / 89,600 N = 5
Therefore, the factor of safety for the steel hanger is 5.
To find the factor of safety for the steel hanger, we need to compare the actual strength of the hanger with the applied load. The factor of safety is defined as the ratio of the ultimate strength (or yield strength) of the material to the applied load.
First, let's convert the load from kilonewtons to newtons:
89.6 kN = 89.6 × 1000 N = 89,600 N
Now, calculate the ultimate strength of the hanger in newton per cm2:
70,000 N/cm2
Next, we can calculate the actual strength of the hanger by multiplying the ultimate strength (70,000 N/cm2) by the cross-sectional area of the hanger (6.4 cm2):
Actual Strength = 70,000 N/cm2 × 6.4 cm2 = 448,000 N
Now, we can calculate the factor of safety by dividing the actual strength by the applied load:
Factor of Safety = Actual Strength / Applied Load
Factor of Safety = 448,000 N / 89,600 N = 5
Therefore, the factor of safety for the steel hanger is 5.