If Tan (A+B)=1/3 and Tan(A-B)=2/5,then prove that
A.Tan2A=11/13
B.Tan2B=-1/17
Let
x = arctan(1/3)
y = arctan(2/5)
A+B = x
A-B = y
2A = x+y
tan2A = tan(x+y)
= (tanx+tany)/(1-tanx*tany)
= (1/3 + 2/5)/(1-(1/3)(2/5))
= 11/13
do 2B the same way
WOW....you are very creative ....
Good
It is really very short ans plz put long ans soo that we can understand
Thank you sir
How can he keep arctan 1/3 as x.
X must be kept as 1/3 and while putting the value of x There should be Tanx=Tan 1/3