vapour density of gas is 11.2 volume occupied by 22.4gms at STP?
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To calculate the volume occupied by a gas at STP (Standard Temperature and Pressure) when given the vapor density and mass of the gas, you can use the following steps:
1. Determine the molar mass of the gas: The molar mass of a gas is the mass of one mole of that gas. In this case, the vapor density is given as 11.2, which represents the ratio of the density of the gas to the density of hydrogen (which is taken as 1). To find the molar mass, you multiply the vapor density by the molar mass of hydrogen (2 g/mol). So, in this case, the molar mass of the gas would be 11.2 * 2 = 22.4 g/mol.
2. Use the molar mass to find the number of moles: Divide the mass of the gas (given as 22.4 g) by the molar mass of the gas (found in step 1). In this case, dividing 22.4 g by 22.4 g/mol gives us 1 mole of the gas.
3. Use the Avogadro's Law to find the volume: Avogadro's Law states that equal volumes of gases at the same temperature and pressure will contain the same number of molecules. At STP, one mole of gas occupies 22.4 liters. Therefore, in this case, the volume occupied by the gas would be 22.4 liters.
So, the volume occupied by 22.4 grams of a gas with a vapor density of 11.2 at STP is 22.4 liters.