The density of the ice is 918kgm-3 and that of water is 1030kgm-3. An iceberg floats with a portion of 224 litre outside water. Find the volume of the iceberg.
Not sure about answer. But I think it is wrong answer.........
To find the volume of the iceberg, we need to understand the principle behind floating objects. According to Archimedes' principle, an object will float if it displaces an amount of water equal to its own weight.
In this case, we have an iceberg floating with a portion of 224 liters (or 0.224 cubic meters) outside the water.
Let's assume the volume of the iceberg is V cubic meters.
To find the volume of the iceberg, we need to find the volume of water it displaces.
The portion of the iceberg outside the water is equal to the volume of water displaced by the iceberg. Therefore, the volume of water displaced is also 0.224 cubic meters.
Assuming both ice and water have the same density (which is a reasonable approximation), the mass of the water displaced is equal to the mass of the iceberg.
Density = Mass / Volume
Rearranging this equation, we have:
Mass = Density * Volume
Since the density of water is 1030 kg/m³ and the volume of water displaced is 0.224 m³, we can calculate the mass of the iceberg as:
Mass = 1030 kg/m³ * 0.224 m³ = 230.72 kg
Now that we know the mass of the iceberg, we can use the density of ice (918 kg/m³) to find the iceberg's volume:
Volume = Mass / Density
Volume = 230.72 kg / 918 kg/m³ ≈ 0.251 m³
Therefore, the volume of the iceberg is approximately 0.251 cubic meters.
Here,
First of all we will convert 224 litres into m³ as 1l = 1000m³
= 224l = 224/1000 m³
Now ,
Density of iceberg = DVG
density of water = dvg
DVG = dvg
918 × V= 1030×224/1000....(1)
V= volume of iceberg
From ...(1)
0.25 m³....@nswer
Vb = (918/1030)*V = V-224. = Vol. below surface.
V = 2036 Liters.
918/1030 = 89.12%
That means that 10.88% of the berg is showing.
so, 224 = 0.1088v