A bicycl rider starts from rest and moves with uniform acceration of 1.5m\s^2 it is velocity reachs 7.5m\s of a distance .......
d=v*t
d=7.5*5=35.5m
V = a*t = 7.5 m/s.
1.5*t = 7.5.
t = 5 s.
d = 0.5a*t^2 = 0.5*1.5*5^2 = 18.75 m.
To find the distance covered by the bicyclist, we can use the equation of motion:
distance = (initial velocity * time) + (1/2 * acceleration * time^2)
In this case, the initial velocity is 0m/s because the cyclist starts from rest, the acceleration is 1.5m/s^2, and the final velocity is 7.5m/s.
We can rearrange the equation to solve for time:
distance = (0 * time) + (1/2 * 1.5 * time^2)
distance = 0 + 0.75 * time^2
distance / 0.75 = time^2
sqrt(distance / 0.75) = time
Now, substitute the value of final velocity (7.5m/s) into the equation to find the distance covered:
distance = (0 * time) + (1/2 * 1.5 * time^2)
distance = 0 + 0.75 * time^2
7.5 = 0 + 0.75 * time^2
7.5 / 0.75 = time^2
10 = time^2
time = sqrt(10)
Substituting the value of time back into the equation, we can find the distance:
distance = (0 * sqrt(10)) + (1/2 * 1.5 * (sqrt(10))^2)
distance = 0 + 0.75 * 10
distance = 0 + 7.5
distance = 7.5 meters
Therefore, the distance covered by the bicyclist is 7.5 meters.