wright the slope-intercept form of the equation of the line described though:(-2,5), parallel to y=-9/2x+3

And another misspelled post from the person in Texas who seems to have an identity problem.

Slope of parallel lines are the same. m = -9/2 here so the new line will have a slope of m= -9/2 as well.

Through the points (-2,5)

y-y1=m(x-x1)
y-5=(-9/2)(x--2)
y-5=(-9/2)(x+2)
y-5=(-9/2)x+(-9)

y=(-9/2)x-4.

Or, using

y(x) = -9/2 x + 3,
y(-2) = 9+3 = 12

You want y(-2) = 5, so you have to subtract 7 from the given value, leaving you with

y = -9/2 x - 4

To find the slope-intercept form of the equation of a line given a point and a parallel line, you need to use the following steps:

1. Identify the slope of the given line: The given line is in slope-intercept form, y = mx + b, where m is the slope. In this case, the slope of the given line is -9/2.

2. Since the desired line is parallel to the given line, the slopes of both lines will be the same. Therefore, the slope of the desired line will also be -9/2.

3. Use the point-slope form of the equation of a line, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Using the point (-2, 5) and the slope -9/2, we substitute these values into the point-slope form:

y - 5 = -9/2(x - (-2))

Simplifying:

y - 5 = -9/2(x + 2)

Now, convert the equation to slope-intercept form, y = mx + b, by expanding the expression on the right-hand side:

y - 5 = -9/2x - 9/2(2)

y - 5 = -9/2x - 9/2(2/1)

y - 5 = -9/2x - 9/1

y - 5 = -9/2x - 18/2

y - 5 = -9/2x - 9

Finally, add 5 to both sides of the equation to isolate y:

y = -9/2x - 9 + 5

y = -9/2x - 4

Therefore, the slope-intercept form of the equation of the line described is y = -9/2x - 4.