The hook of a spring balance carries an object of mass 5kg And the balance is suspended vertically from the roof of a lift. Find the reading on the spring balance when the lift is going down with an acceleration of 0.1m/s^2? g=10m/s^2

To find the reading on the spring balance, we need to consider the forces acting on the object.

The force acting on the object is the gravitational force, which can be calculated as the product of mass (m) and acceleration due to gravity (g):

F_gravity = m * g

Given:
m (mass of the object) = 5 kg
g (acceleration due to gravity) = 10 m/s^2

F_gravity = 5 kg * 10 m/s^2
= 50 N

Since the lift is going down with an acceleration of 0.1 m/s^2, we need to account for the additional force due to this acceleration.

The net force acting on the object is the sum of the gravitational force and the force due to acceleration:

F_net = F_gravity + F_acceleration

F_acceleration = m * a
= 5 kg * 0.1 m/s^2
= 0.5 N

F_net = 50 N + 0.5 N
= 50.5 N

Finally, the reading on the spring balance will be equal to the net force acting on the object, which is 50.5 N.

To calculate the reading on the spring balance when the lift is going down with an acceleration of 0.1 m/s^2, we need to consider the forces acting on the object.

First, let's find the force acting on the object due to gravity. The force due to gravity can be calculated using the equation:

F_gravity = mass * acceleration_due_to_gravity

where mass is the mass of the object and acceleration_due_to_gravity is the acceleration due to gravity (g = 10 m/s^2).

F_gravity = 5 kg * 10 m/s^2
F_gravity = 50 N

The force acting on the object due to gravity is 50 N.

Next, let's consider the force acting on the object due to the acceleration of the lift. The force due to acceleration can be calculated using the equation:

F_acceleration = mass * acceleration

where mass is the mass of the object and acceleration is the acceleration of the lift (-0.1 m/s^2 because the lift is going down).

F_acceleration = 5 kg * (-0.1 m/s^2)
F_acceleration = -0.5 N

The force acting on the object due to the acceleration of the lift is -0.5 N (negative sign indicates the direction of the force).

To calculate the reading on the spring balance, we need to consider the net force acting on the object. The net force can be calculated by adding up the forces acting on the object:

Net force = F_gravity + F_acceleration
Net force = 50 N + (-0.5 N)
Net force = 49.5 N

The net force acting on the object is 49.5 N.

Therefore, the reading on the spring balance when the lift is going down with an acceleration of 0.1 m/s^2 would be 49.5 N.