Rodney and Cauls’s houses having distance of eleven km Rodney start from his house by walking at the speed of 6 km / hr , Caouls at 5 km / hr at what distane they will meet , if Rodney start his journey later by 5 minutes then which time they will meet ?

A. d = 6t + 5t = 11 km.

11t = 11.
t = 1 hr. = Time they meet.

d1 = 6km/h * 1h = 6km. = Distance Rodney
traveled when they met.

d2 = 5km/h * 1h = 5km = Distance Ca0uls
traveled.

B. 6(t-1/12) + 5t = 11 km.
6t-0.5 + 5t = 11.
11t = 11.5.
t = 1.045 h.