the product of the sum and the difference of two nu8mberts is 105. find the two numbers

(x+y)(x-y) = 105

Since 105 = 3*5*7, I suspect that
x-y is one of those values.

Now, 105 = 3*35 or 5*21 or 7*15
So, we can try

x-y=3
x+y=35
(x,y) = (19,16)

x-y=5
x+y=21
(x,y) = (13,8)

x-y=7
x+y=15
(x,y) = (11,4)