To form a certain sequence, the rules are:

1)If a number is even, divide by 2 to get the next number

2)If a number is odd, multiply by 3, then add 1 to the the next number.

Starting with 12,the 1000th term would be...
a.1
b.2
c.3
d.4

THANKS

Someone

well, let's see what happens.

12
6
3
10
5
16
8
4
2
1
4
2
1
4
2
1
tarting with T8, they repeat with a period of 3
1000 = 7+993 = 7+3*331

So, T1000 = 1

To find the 1000th term of the given sequence, we can use the rules provided:

1) If a number is even, divide by 2 to get the next number.
2) If a number is odd, multiply by 3, then add 1 to get the next number.

Starting with 12, let's apply these rules step by step to generate the sequence until we reach the 1000th term:

Term 1: 12
Since 12 is even, we divide it by 2 to get the next term: 6.

Term 2: 6
Since 6 is even, we divide it by 2 to get the next term: 3.

Term 3: 3
Since 3 is odd, we multiply it by 3 and add 1 to get the next term: 10.

Term 4: 10
Since 10 is even, we divide it by 2 to get the next term: 5.

Term 5: 5
Since 5 is odd, we multiply it by 3 and add 1 to get the next term: 16.

Term 6: 16
Since 16 is even, we divide it by 2 to get the next term: 8.

Term 7: 8
Since 8 is even, we divide it by 2 to get the next term: 4.

Term 8: 4
Since 4 is even, we divide it by 2 to get the next term: 2.

Term 9: 2
Since 2 is even, we divide it by 2 to get the next term: 1.

Term 10: 1
Since 1 is odd, we multiply it by 3 and add 1 to get the next term: 4.

Term 11: 4
Since 4 is even, we divide it by 2 to get the next term: 2.

Term 12: 2
Since 2 is even, we divide it by 2 to get the next term: 1.

As you can see, the sequence starting with 12 repeats indefinitely between the terms 1, 2, and 4. Therefore, the 1000th term of the sequence would also be 1.

So, the answer is:
a. 1