A fruit seller had 450 apples and pears.He sold 1/2 of the apples and 1/4 of the pears. He had a total of 265 apples and pears lefty How

many more apples than pears did he have at first.

Thanks😊

Just write down in symbols what they told you. If there are a apples and p pears, then

a+p = 450
(1/2)a + (3/4)p = 265

a=290
p=160

a-p = 130

It will help if anyone answer me by today.😊

Thanks a lot.😊

To answer this question, we need to break it down into a few steps.

Step 1: Calculate the number of apples and pears the fruit seller sold.
The fruit seller sold 1/2 of the apples, which means he sold 1/2 * 450 = 225 apples.
He also sold 1/4 of the pears, which means he sold 1/4 * 450 = 112.5 pears.

Since you can't have half of a fruit, we need to round the number of sold pears. In this case, we'll round down to 112 pears (as there is no such thing as half a pear).

Step 2: Calculate the number of apples and pears the fruit seller had left.
The fruit seller had 450 - 225 = 225 apples left.
He also had 450 - 112 = 338 pears left.

Step 3: Calculate the difference between the number of apples and pears the fruit seller had at first.
The difference between the number of apples and pears the fruit seller had at first is given by 225 - 112 = 113.

Therefore, the fruit seller had 113 more apples than pears at first.