find the equation of the curve for which y''=(12/x^3) if it passes through (1,0) and is tangent to the line 6x+y=6 at that point.
Its slope is the same as of y = -6x+6
or slope = -6 at (1,0)
so do it just like I did the other one.
or slope = -6 at (1,0)
so do it just like I did the other one.