The student used the KHP in a subsequent titration experiment where he titrated 25.00 +/- 0.03 ml of the acid against an unknown solution of NaOH. The titration required 23.70 +/- 0.10 ml of the base. What is the concentration of NaOH?

KHP + NaOH ==> NaKP + H2O

mols KHP = mols NaOH; therefore, you can use
mL KHP x M KHP = mL NaOH x M NaOH

There is no way this question can be answered without the concentration of the acid.

To calculate the concentration of NaOH, we first need to find the number of moles of NaOH used in the titration. We can then use this information to calculate the concentration.

Step 1: Calculate the number of moles of KHP used in the titration.
The molar mass of KHP (potassium hydrogen phthalate) is needed in this step. The molar mass of KHP is 204.23 g/mol.

Given:
Volume of KHP solution used = 25.0 +/- 0.03 ml = 0.0250 +/- 0.00003 L

Step 2: Calculate the number of moles of KHP.
The molarity of KHP can be calculated using the formula:
Molarity (M) = moles of solute (KHP) / volume of solution used (L)

Molarity of KHP = 0.1 M (given)

Number of moles of KHP = Molarity of KHP x volume of solution used (L)
= 0.1 M x 0.0250 +/- 0.00003 L

Step 3: Calculate the number of moles of NaOH used in the titration.
Based on the balanced chemical equation for the reaction between KHP and NaOH, we know that 1 mole of KHP reacts with 1 mole of NaOH.

Therefore, the number of moles of NaOH used in the titration is equal to the number of moles of KHP used.

Number of moles of NaOH = Number of moles of KHP
Number of moles of NaOH = 0.1 M x 0.0250 +/- 0.00003 L

Step 4: Calculate the concentration of NaOH.
Now, we can use the number of moles of NaOH and the volume of NaOH used to calculate the concentration.

Given:
Volume of NaOH used = 23.70 +/- 0.10 ml = 0.0237 +/- 0.0001 L

Concentration of NaOH = Number of moles of NaOH / volume of NaOH used (L)
= 0.1 M x 0.0250 +/- 0.00003 L / 0.0237 +/- 0.0001 L

By performing the calculation, you will get the concentration of NaOH.