A torque of 32Nm is applied to a wheel, which causes it to accelerate at 25 rad/s2. What is the rotational moment of inertia of the wheel?
I got 1.28kg/m^2.
To find the rotational moment of inertia of the wheel, you can use the equation:
Torque (τ) = Moment of Inertia (I) * Angular Acceleration (α)
Given:
Torque (τ) = 32 Nm
Angular Acceleration (α) = 25 rad/s²
Rearranging the equation, we get:
I = τ / α
Substituting the given values, we have:
I = 32 Nm / 25 rad/s²
I = 1.28 kg·m²
So, the rotational moment of inertia of the wheel is indeed 1.28 kg·m². Well done on getting the correct answer!