an element 'x' react with water to form a solution which turns phenolphthalein indicator pink .The element 'x' is most likely
a) sulphur
b) sodium
c) carbon
d) silicon
sodium + H2O is a bit violent
I would bet on S because H2S is not only stinky but acid
S won't do it since it isn't soluble in water. (C and Si are not soluble either). The answer is sodium.
2Na + 2H2O ==> H2 + 2NaOH and NaOH is a strong base which will turn phenolphthalein pink.
Glad you came along DrBob !
Sodium
Sodium
To determine the most likely element 'x', we need to analyze the information given.
In this case, we are told that when element 'x' reacts with water, it forms a solution that turns phenolphthalein indicator pink.
Phenolphthalein is an indicator commonly used to test for acidity or alkalinity. It is colorless in acidic solutions and turns pink in basic or alkaline solutions.
Based on this information, we can infer that element 'x' reacts with water to produce a basic or alkaline solution, as it turns the phenolphthalein indicator pink.
Among the options given (sulfur, sodium, carbon, and silicon), the element that is most likely to react with water to form a basic solution is sodium (option b). Sodium is a highly reactive metal that readily reacts with water to produce sodium hydroxide, which is a strong base.
Therefore, the most likely element 'x' in this scenario is sodium.