A baseball team played 149 complete games last season. They had 31 fewer wins than losses. How many games did the team win?

They won less than half their games.

What is your answer?

Let x = number of games won.

x + x + 31 = 149

2x = 118

x = ?

59!

Yay! :-)

Right. They won 59 games.

To find out how many games the team won, we need to set up an equation based on the information given. Let's assume the number of wins is represented by W and the number of losses is represented by L.

From the given information, we know that the team played 149 complete games. This means that the total number of wins and losses should add up to 149. We can write this as the equation:

W + L = 149 --------------- Equation 1

We are also told that the team had 31 fewer wins than losses. Mathematically, we can express this as:

W = L - 31 -------------------- Equation 2

Now we have a system of two equations with two variables. We can solve this system by substitution or elimination. Let's use substitution.

We'll substitute the value of W from Equation 2 into Equation 1:

(L - 31) + L = 149

Combining like terms:
2L - 31 = 149

Adding 31 to both sides:
2L = 180

Dividing both sides by 2:
L = 90

Now, we can substitute this value of L back into Equation 2 to find the value of W:

W = 90 - 31
W = 59

Therefore, the team won 59 games.