calculate the osmotic pressure at 18.5 degree celcuis of a suspension containing 30g/L of solid particles. each particle weighs 10^-9g.
To calculate the osmotic pressure, we can use the formula:
Osmotic Pressure (π) = (Molarity of particles) * (Gas constant, R) * (Temperature in Kelvin)
First, we need to find the molarity of the particles:
Molarity (M) = (Number of moles of particles) / (Volume in liters)
To find the number of moles of particles, we need to know the mass and molar mass of the particles. Since each particle weighs 10^(-9) grams and the suspension contains 30 grams of solid particles per liter, we can calculate the molar mass:
Molar mass of particles = (Mass of particles) / (Number of moles)
Molar mass of particles = 10^(-9) g
Now, we need to convert the temperature from Celsius to Kelvin:
Temperature in Kelvin = (Temperature in Celsius) + 273.15
Given that the temperature is 18.5°C, the temperature in Kelvin will be:
Temperature in Kelvin = 18.5°C + 273.15 = 291.65 K
Now, let's put all the values into the formula to calculate the osmotic pressure:
Molarity (M) = (30 g/L) / (10^(-9) g) = 3 * 10^10 moles/L
Osmotic Pressure (π) = (3 * 10^10 moles/L) * (Gas constant, R) * (291.65 K)
The gas constant, R, is equal to 0.0821 L * atm / (mol * K).
Finally, plug the values into the formula to find the osmotic pressure.