50% of cars produced have A/C. 52 cars are produced each day. If we did 10 consecutive days of production, what is the probability that 5 had A/C?
prob(A/C) = 1/2
prob(not A/C) = 1/2
prob(that 5 out of 10 have A/C)
= C(10,5)(1/2)^5 (1/2)^5
= 252 (1/2)^10
=252/1024
= 63/256 or appr .246