A 100 kg trunk loaded with old books is to be slid across a floor by a young woman who
exerts a force 300 N down and forward at 30° with the horizontal. If µs = 0.5 and µk =
0.5, compute the resulting acceleration.
push force forward = 300 cos 30 = 260 N
push force down = 300 sin 30 = 150 N
normal force = 100*9.81 + 150 = 1131 N
static maximum friction = 1131*.5 = 565 N
so it does not budge and we need an older stronger woman or you have typos. It is unlikely that u static and u kinetic are both .5