Question

npr=3024 find r

(2)dy/dx=secx-tanx/secx+tanx. plz help

Answer 1

If npr=3024, r=3024/np

y' = (secx-tanx)/(secx+tanx)
y' = (secx-tanx)^2/tan^2x
y' = csc^2x - 2cscx + 1

Those are straightforward integrals