Carbon tetracholoride is made according to the following reaction: carbon disulfide + chlorine gas yields carbon tetrachloride and disulfur dichloride. Write the correct balanced equation and then determine how many grams of CS2 are needed to make 16 kilograms of CCl4.
(PLEASE HELP!! Its extra credit but i cant figure out the answer)
mols CCl4 is correct at 104.
Now you want to go to step 2 and convert mols CCl4 to mols CS2. That is done this way using the coefficients in the balanced equation.
104 mols CCl4 x (1 mol CS2/1 mol CCl4) = ?
The problem tells you the reactants and products. Copy those down, then balance it.
CS2 + 3Cl2 ==> CCl4 + S2Cl2
Then the problem part.
16 kg = 16,000 g
mols CCl4 = grams CCl4/molar mass CCl4 = ?
Using the coefficients in the balanced eaquation, convert mols CCl4 to mols CS2.
Now convert mols CS2 to grams CS2 by g = mols CS2 x molar mass CS2.
This is a regular stoichiometry problem. Print this out and save it. It will work about 90% (or more) of the stoichiometry problems you will have.
Carbon tetracholoride is made according to the following reaction: carbon disulfide + chlorine gas yields carbon tetrachloride and disulfur dichloride. Write the correct balanced equation and then determine how many grams of CS2 are needed to make 16 kilograms of CCl4.
CS2 + 3Cl2 ==> CCl4 + S2Cl2
Mols CCl4 = 104.01
AFER THAT IM LOST :(
What DrBob222 said: the step after that is to convert moles of CCl4 to moles of CS2. Seeing as you are still confused after being told the steps, I imagine you don't know how to do that. To convert from moles between substances, cross multiply the moles of the original substance's actual moles by the coefficient of the substance one is converting to, and then divide by the original substance's coefficient. I'd never understand how to so it just from those words, so here's an example: 2A+3B=5C+4D is a balanced chemical reaction. To figure out how many moles of C 3 moles of A can produce, one would take the moles of the original substance, 3, multiply it by the coefficient of the substance one is converting to, 5, and divide by the original substance's coefficient, 2. 3*5/2, which would equal 7.5 moles. 3 moles of B produce 7.5 moles of C. In your situation, though, it is a lot simpler, because the coefficients are one to one. This makes it so that the moles are equal. Ex:A+B=C. 2 moles of A are required to make 2 moles of C, 6 moles of C can be yielded from 6 moles of A reacting with 6 moles of B. I'm sorry for being so lengthy, I miss chemistry class. I hope this explanation was understandable.
Hey Dilcia!!!
turns out im in the same online chemistry class as you and I think i figured out this problem.
So we know our equation is:
CS2 + 3Cl2 ==> CCl4 + S2Cl2
We set up the problem
16 kg CCl4 | 1 mol CCl4 | 1 mol CS2 | 0.076 kg CS2 |
| 0.15 kg CCI4 | 1 mol CCl4 | 1 mol CS2 |
The unit of measurement cancels out and you get 13.376/.15= 89.1733 kg CS2
So your final answer is: 89173.3 g of CS2