The formula for rust can be represented by Fe2O3. How many moles of Fe are present in 24.6 g of the compound? Please guide me through it thank you!
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To determine the number of moles of Fe in the compound Fe2O3, we need to use the molar mass of Fe and the given mass of the compound.
1. Determine the molar mass of Fe:
- The atomic mass of Fe from the periodic table is approximately 55.85 g/mol.
2. Calculate the molar mass of Fe2O3:
- Fe2O3 contains two atoms of Fe, each with a molar mass of 55.85 g/mol, and three atoms of oxygen (O) with a molar mass of 16.00 g/mol.
- So, the molar mass of Fe2O3 = (2 * molar mass of Fe) + (3 * molar mass of O) = (2 * 55.85 g/mol) + (3 * 16.00 g/mol).
3. Use the molar mass of Fe2O3 to convert the given mass to moles:
- Given: mass of Fe2O3 = 24.6 g.
- Moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3.
- Moles of Fe = (moles of Fe2O3) * (2 moles of Fe / 1 mole of Fe2O3).
Now, let's calculate the number of moles of Fe using the given information:
1. Molar mass of Fe = 55.85 g/mol.
2. Molar mass of Fe2O3 = (2 * 55.85 g/mol) + (3 * 16.00 g/mol) = 159.70 g/mol.
3. Moles of Fe2O3 = 24.6 g / 159.70 g/mol.
4. Moles of Fe = (moles of Fe2O3) * (2 moles of Fe / 1 mole of Fe2O3).
Using the calculated moles of Fe, you will find the number of moles of Fe in 24.6 g of Fe2O3.