Customers of a phone company can choose between two service plans for long distance calls. The first plan has a

$14 monthly fee and charges an additional
$0.20 for each minute of calls. The second plan has an $18 monthly fee and charges an additional $0.15 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?

let m be the number of minutes

cost1 = .20m + 14
cost2 = .15m + 18

When is .20m + 14 = .15m + 18 ?

.05m = 4
m = 4/.05 = 80

250

To find the number of minutes of calls for which the costs of the two plans are equal, we can set up an equation.

Let's assume the number of minutes of calls is represented by 'm'.

For the first plan, the cost can be calculated as:
Cost of calls in the first plan = $14 + $0.20 * m

For the second plan, the cost can be calculated as:
Cost of calls in the second plan = $18 + $0.15 * m

We want to find the number of minutes of calls (m) for which the costs are equal, so we can set up the equation:

$14 + $0.20 * m = $18 + $0.15 * m

Now, let's solve this equation to find the value of 'm'.

$0.20 * m - $0.15 * m = $18 - $14
$0.05 * m = $4
m = $4 / $0.05
m = 80

Therefore, the costs of the two plans will be equal when the number of minutes of calls is 80 minutes.

To find the number of minutes of calls for which the costs of the two plans will be equal, we need to set up an equation based on the given information.

Let's say x represents the number of minutes of calls.

For the first plan, the total cost can be expressed as:
Cost 1 = $14 (monthly fee) + $0.20 (per minute charge) * x (number of minutes of calls)

For the second plan, the total cost can be expressed as:
Cost 2 = $18 (monthly fee) + $0.15 (per minute charge) * x (number of minutes of calls)

To find the number of minutes of calls for which the costs are equal, we can set up the equation:

14 + 0.20x = 18 + 0.15x

Now we can solve this equation for x:

0.20x - 0.15x = 18 - 14
0.05x = 4
x = 4 / 0.05
x = 80

Therefore, the costs of the two plans will be equal for 80 minutes of calls.