A golf cart has an acceleration of 0.4 m/s². What is its velocity after it has covered 10 m starting from the rest?
10 = (1/2)(.4) t^2
solve for t
v = 0 + .4 t
10.2
To find the velocity of the golf cart after it has covered a certain distance, we can use the kinematic equation:
\(v^2 = u^2 + 2as\)
Where:
- \(v\) is the final velocity of the golf cart
- \(u\) is the initial velocity (rest, so \(u = 0\))
- \(a\) is the acceleration of the golf cart (0.4 m/s²)
- \(s\) is the distance covered (10 m)
To solve for \(v\), we can rearrange the equation:
\(v^2 = 0^2 + 2 \cdot 0.4 \cdot 10\)
Simplifying the equation gives us:
\(v^2 = 8\)
To find \(v\), we take the square root of both sides:
\(v = \sqrt{8}\)
Using a calculator, we find that:
\(v \approx 2.83\) m/s
So, the velocity of the golf cart after covering 10 m is approximately 2.83 m/s.