Suppose Paul kicks a soccer ball straight up into the air with an initial velocity of 96 feet per second. The function f(x) = -16t2 + 96t gives the height, in feet, of the soccer ball after t seconds
What are the zeros?
Write the number(s) only. If more than one number exists, separate by a comma
factor it to get
-16t(t-6)
That should help
To find the zeros of a function, we need to determine the values of x (or in this case, t) for which the height of the soccer ball is zero. In other words, we need to solve the equation f(t) = -16t^2 + 96t = 0.
To solve this quadratic equation, we can factor out a common factor of t: t(-16t + 96) = 0. Now we have two factors: t = 0 and -16t + 96 = 0.
Simplifying the second equation, we get -16t + 96 = 0. Rearranging the equation, we have -16t = -96. Dividing both sides by -16, we find t = 6.
Therefore, the zeros (or x-intercepts) of the function f(t) = -16t^2 + 96t are t = 0 and t = 6.