A photon of light has a wavelength of about 600 nm (1nm = 1 x 10-9 m). What is the energy of this photon of light? Show all calculations leading to an answer.

find the frequency from the wavelength

lambda = c T = c/f
then energy = Lank constant * frequency

ok thank you so much, have a great day :)

Given: wavelength=600 nm; h=6.62×10^-34

Solution:
Since, Energy=hc/wavelength
(6.62×10^-34×3.0×10^8)/600×10^-9
=3.39×10^-19J
=3.39×10^-19/1.6×10^-19 eV
=2.11875 eV

To calculate the energy of a photon, you can use the equation:

E = h * c / λ

Where:
E is the energy of the photon
h is the Planck's constant (approximately 6.626 x 10^-34 J·s)
c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s)
λ is the wavelength of the photon

Given that the wavelength of the photon is 600 nm (or 600 x 10^-9 m), we can substitute the values into the equation and solve for E.

E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (600 x 10^-9 m)

First, we can simplify the values in the numerator:

(6.626 x 3.00) * 10^-34 J·s·m/s

Next, we can simplify the values in the denominator:

600 * 10^-9 m = 6.00 x 10^-7 m

Now we can substitute the simplified values back into the equation:

E = (6.626 x 3.00) * 10^-34 J·s·m/s / (6.00 x 10^-7 m)

Using multiplication and division:

E = 19.878 x 10^-34 J·s·m/s / 6.00 x 10^-7 m

Simplifying further:

E = 3.313 x 10^-27 J

Therefore, the energy of the photon with a wavelength of 600 nm is approximately 3.313 x 10^-27 J.