A 2.50 kg fireworks shell is fired straight up from a mortar intending to reach 110m. How much downward force is created to propel that shell upwards to it's intended target?
I think you need to specify more.
F=ma, but we don't know how long it took to reach its ballistic speed, so we have no idea of the initial acceleration.
To calculate the downward force required to propel the fireworks shell upwards, we need to consider the principles of projectile motion and Newton's laws of motion.
In this case, we can determine the downward force by analyzing the forces acting on the shell during its ascent. The main forces involved are gravity and air resistance.
First, let's calculate the force of gravity acting on the shell. The force of gravity can be calculated using the equation:
Fg = m * g
where Fg is the force of gravity, m is the mass of the shell, and g is the acceleration due to gravity (approximately 9.8 m/s² on Earth). Plugging in the values:
Fg = (2.50 kg) * (9.8 m/s²) = 24.5 N
Therefore, the force of gravity acting on the shell is 24.5 Newtons.
Now, we need to consider air resistance. Since we don't have specific information about the shell's speed or shape, it's difficult to accurately calculate the exact force of air resistance. Air resistance is a complex force influenced by factors like shape, speed, and air density. However, we can assume that the upward force from the explosion in the mortar is enough to overcome the resistance and propel the shell upwards.
So, in the absence of specific information about air resistance, we can conclude that the downward force required to propel the shell upwards is mainly due to the force of gravity, which is approximately 24.5 Newtons.