Margo and Carrie are trying to go to Idaho for Dawn's wedding. The probability of finding a flight for less than $400 is 1/7. The probability of Carrie making enough money babysitting to pay for her flight is 3/5. The probability of the girls being able to take time off from work is 1/2. What is the probability that they will make it to their friend's wedding?

A. 5/14
B. 1/14
C. 3/70
D. 3/10

(1/7)(3/5)(1/2) = ?

Thank you.

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To find the probability that Margo and Carrie will make it to their friend's wedding, we need to find the intersection of all three events: finding a flight for less than $400, Carrie making enough money babysitting, and the girls being able to take time off from work.

The probability of finding a flight for less than $400 is given as 1/7. This means that there is a 1/7 chance of the flight being affordable.

The probability of Carrie making enough money babysitting to pay for her flight is given as 3/5. This means that there is a 3/5 chance of her earning enough money.

The probability of the girls being able to take time off from work is given as 1/2. This means that there is a 1/2 chance of them being able to take time off.

To find the probability of all three events occurring, we multiply the probabilities together:

(1/7) * (3/5) * (1/2) = 3/70

Therefore, the probability that Margo and Carrie will make it to their friend's wedding is 3/70.

So the correct answer is C. 3/70.