Ahmed buys two dozen eggs. As he is cooking one day he discovers that three of the two dozen eggs have double yolks! Based on this experiment, what is the experimental probability of selecting a double yolk egg from a pack of eggs?
A.10%
B. 12%
C. 12.5%
D. 25 %
I think is 25% because it says from a pack meaning one ; so from a dozen; so p=3/12=1/4
which is 25%. Am I right? Thank you.
"three of the two dozen eggs have double yolks"
3/24 = 1/8 = 12.5%
Thank you.
You're welcome.
Yes, you are correct! Let's break down the problem to understand how you arrived at the answer.
Ahmed buys two dozen eggs, which means he has 24 eggs in total. Out of these 24 eggs, he found three eggs with double yolks.
To find the experimental probability, we need to determine the number of favorable outcomes (double yolk eggs) divided by the total number of possible outcomes (total number of eggs).
Favorable outcomes: 3 (number of double yolk eggs)
Total outcomes: 24 (total number of eggs)
Experimental probability (P) = Number of favorable outcomes / Total number of outcomes
P = 3 / 24
To simplify the fraction, we can divide both the numerator and denominator by 3:
P = (3 / 3) / (24 / 3)
P = 1 / 8
Now, to express the probability as a percentage, we multiply the fraction by 100:
P = (1 / 8) * 100
P = 12.5%
Therefore, the experimental probability of selecting a double yolk egg from a pack of eggs is 12.5%. So, the correct answer is C. 12.5%.
Well done on figuring it out! If you have any more questions, feel free to ask.